(4y^1-5)(4y^2+5)=

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Solution for (4y^1-5)(4y^2+5)= equation: 


Simplifying
(4y + -5)(4y2 + 5) = 0

Reorder the terms:
(-5 + 4y)(4y2 + 5) = 0

Reorder the terms:
(-5 + 4y)(5 + 4y2) = 0

Multiply (-5 + 4y) * (5 + 4y2)
(-5(5 + 4y2) + 4y * (5 + 4y2)) = 0
((5 * -5 + 4y2 * -5) + 4y * (5 + 4y2)) = 0
((-25 + -20y2) + 4y * (5 + 4y2)) = 0
(-25 + -20y2 + (5 * 4y + 4y2 * 4y)) = 0
(-25 + -20y2 + (20y + 16y3)) = 0

Reorder the terms:
(-25 + 20y + -20y2 + 16y3) = 0
(-25 + 20y + -20y2 + 16y3) = 0

Solving
-25 + 20y + -20y2 + 16y3 = 0

Solving for variable 'y'.

The solution to this equation could not be determined.

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